Two circles touch each other externally at T. RS is a direct common tangent to the two circles touching the circles at P and Q. ∠TPQ = 42°. ∠PQT (in degrees) is:

Answer: Option A

In ΔPTQ
∠QPT + ∠PTQ + ∠PQT = 180°
42° + 90° + ∠PQT = 180°
∠PQT = 180° - 132°
∠PQT = 48°