Two dice are thrown simultaneously. What is the probability of getting the sum of the face number is at least 10?

Answer: Option B

In a simultaneous throw of two dice, we have n(s) = 6 × 6 = 36
Let E = event of getting two number whose sum is at least 10
Then E = {(4,6), (5,5), (5,6), (6,4), (6,5), (6,6)}
therefore, n(E) = 6
And p(E) = p(getting two numbers whose sum is at least 10)
$$\begin{array}{rl}& \text{p}\left(\text{E}\right)=\frac{\text{n}\left(\text{E}\right)}{\text{n}\left(\text{S}\right)}\\ & =\frac{6}{36}\\ & =\frac{1}{6}\end{array}$$
Hence the answer is $$\frac{1}{6}$$