Two dice are thrown simultaneously. What is the probability of getting the sum of the face number is at most 5?

Answer: Option D

In a simultaneous throw of two dice, we have n(s) = 6 × 6 = 36
Let E = event of getting two numbers whose sum is at most 5
Then E = {(1,1), (1,2), (1,3), (1,4), (2,1), (2,2), (2,3), (3,1), (3,2), (4,1)}
therefore, n(E) = 10
And p(E) = p( getting two numbers whose sum is at most 5)
$$\begin{array}{rl}& \text{p}\left(\text{E}\right)=\frac{\text{n}\left(\text{E}\right)}{\text{n}\left(\text{S}\right)}\\ & =\frac{10}{36}\\ & =\frac{5}{18}\end{array}$$
Hence the answer is $$\frac{5}{18}$$