Two numbers are such that the square of one is 224 less than 8 times…

Question

Two numbers are such that the square of one is 224 less than 8 times the square of the other. If the numbers are in the ratio of 3 : 4, then their values are = ?

Accepted Answer

Option B. 6, 8. Answer & Solution Answer: Option B Solution: & Let number be x\,\&\, y & Given, & \,\,x:y & \,\,\,\,3:4 & \,3a:4a & Now , given that & 8 ( 3a )^2 = ( 4a )^2 + 224 & 72a^2 = 16a^2 + 224 & 56a^2 = 224 & a^2 = 4 & a = 2 & Numbers are & x = 3 × 2 = 6 & y = 4 × 2 = 8