Two trains start from stations A and B and travel towards each other at a speed of 50 kmph and 60 kmph respectively. A the time of their meeting, the second train had travelled 120 km more then the first. The distance between A and B is :

Answer: Option B

At the time of meeting, let the distance travelled by the first train be x km.
Then, discount covered by the second train = (x + 120) km
$$\begin{array}{rl}& \therefore \frac{x}{50}=\frac{x+120}{60}\\ & \iff 60x=50x+6000\\ & \iff 10x=6000\\ & \iff x=600\end{array}$$
So, distance between A and B
= (x + x + 12) km
= 1320 km