Two vessels A and B contain milk 8 : 5 and 5 : 2 respectively. The ratio in which these two mixtures be mixed to get a new mixture containing 69 313 % milk is =?

Answer: Option D

Milk in 1 litre mix. in A = $$\frac{8}{13}$$
Milk in 1 litre mix. in B = $$\frac{5}{7}$$
Milk in 1 litre of final mix. = $$\frac{900}{13}\times \frac{1}{100}\times 1=\frac{9}{13}$$

By the rule of alligation, we have :

∴ Required ratio $$=\frac{2}{91}:\frac{1}{13}=2:7$$