Q2
What is the approximate filament resistance of a light bulb if it operates from a 110 V source and 0.6 A of current is flowing?
A.
183 Ω
AnswerB.
18.3 Ω
C.
66 Ω
D.
6.6 Ω
Answer: Option A
Solution
Answer: Option A
Solution:
This question is about Ohm's Law, which is a fundamental rule in electrical circuits. Ohm's Law tells us how Voltage (V), Current (I), and Resistance (R) are related.
The formula for Ohm's Law is: V = I * R
Where:
* V is the Voltage (measured in Volts)
* I is the Current (measured in Amperes or Amps)
* R is the Resistance (measured in Ohms)
In our question, we know:
* The Voltage (V) is 110 V
* The Current (I) is 0.6 A
We need to find the Resistance (R).
To find R, we can rearrange the formula: R = V / I
Now, let's plug in the values:
R = 110 V / 0.6 A
R ≈ 183.33 Ω
So, the closest answer from the options is 183 Ω.
That means Option A is correct.