Q128
What is the greatest number of 3 digits which when divided by 6, 9 and 12 leaves a remainder of 3 in each case ?
A.
903
B.
939
C.
975
AnswerD.
996
Answer: Option C
Solution
Answer: Option C
Solution:
Greatest number of three digits is 999. LCM of 6, 9 and 12 is 36On dividing 999 by 36, the remainder obtained is 27.
So, required number = (999 - 27) + 3 = 975