What is the least number of square tiles required to pave the floor of a room 15 m 17 cm long and 9 m 2 cm broad?

Answer: Option D

Length of the room
= 15 m 17 cm
= 15 × 100 + 17
= 1517 cm.

Breadth of the room
= 9 m 2 cm
= 902 cm.

The HCF of the 1517 and 902 will be size of square tiles.
HCF 1517 and 902 = 41 cm.

Area of the room
= length × breadth
= 1517 × 902 cm²

Area of tiles = 41 × 41 cm²
So, number of tiles required
= $$\frac{1517\times 902}{41\times 41}$$
= 814 tiles