What is the output of the following code? #include int get_min(int a, int b) if(a<b) return a; return b; int minimum_time_required(int reach[][3],int spent[][4], int *entry, int *exit, int n) int t1[n], t2[n], i; t1[0] = entry[0] + spent[0][0]; t2[0] = entry[1] + spent[1][0]; for(i = 1; i < n; i++) t1[i] = get_min(t1[i-1]+spent[0][i], t2[i-1]+reach[1][i-1]+spent[0][i]); t2[i] = get_min(t2[i-1]+spent[1][i], t1[i-1]+reach[0][i-1]+spent[1][i]); return get_min(t1[n-1]+exit[0], t2[n-1]+exit[1]); int main() int time_to_reach[][3] = 6, 1, 5, 2, 4, 7; int time_spent[][4] = 6, 5, 4, 7, 5, 10, 2, 6; int entry_time[2] = 5, 6; int exit_time[2] = 8, 9; int num_of_stations = 4; int ans = minimum_time_required(time_to_reach, time_spent, entry_time, exit_time, num_of_stations); printf("%d",ans); return 0;

Answer: Option C