What is the output of the following code? #include int get_min(int a, int b) if(a<b) return a; return b; int minimum_time_required(int reach[][4],int spent[][5], int *entry, int *exit, int n) int t1[n], t2[n], i; t1[0] = entry[0] + spent[0][0]; t2[0] = entry[1] + spent[1][0]; for(i = 1; i < n; i++) t1[i] = get_min(t1[i-1]+spent[0][i], t2[i-1]+reach[1][i-1]+spent[0][i]); t2[i] = get_min(t2[i-1]+spent[1][i], t1[i-1]+reach[0][i-1]+spent[1][i]); return get_min(t1[n-1]+exit[0], t2[n-1]+exit[1]); int main() int time_to_reach[][4] = 16, 10, 5, 12, 12, 4, 17, 8; int time_spent[][5] = 13, 5, 20, 19, 9, 15, 10, 12, 16, 13; int entry_time[2] = 12, 9; int exit_time[2] = 10, 13; int num_of_stations = 5; int ans = minimum_time_required(time_to_reach, time_spent, entry_time, exit_time, num_of_stations); printf("%d",ans); return 0;

Answer: Option D