What is the output of the following program? #include int main() int coins[10]=1,3,4,lookup[100]; int i,j,tmp,num_coins = 3,sum=14; lookup[0]=0; for(i=1;i<=sum;i++) int min_coins = i; for(j=0;j<num_coins;j++) tmp=i-coins[j]; if(tmp<0) continue; if(lookup[tmp] < min_coins) min_coins=lookup[tmp]; lookup[i] = min_coins + 1; printf("%d",lookup[sum]); return 0;

Answer: Option C