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Ruby Programming · Q83

Control Structures in Ruby

Programming · Ruby Programming · question 83

Q83

What is the output of the given code? for counter in 1..5 case counter when 0 .. 2 puts counter puts "baby" when 3 .. 6 puts counter puts "little child" when 7 .. 12 puts counter puts "child" else puts counter puts "adult" end end

A.
adult 1..5
B.
3..6 littlechild
C.
1
baby
2
baby
3
little child
4
little child
5
little child
Answer
D.
adult

Answer: Option C

Solution

Answer: Option C
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