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Ruby Programming · Q116

Control Structures in Ruby

Programming · Ruby Programming · question 116

Q116

What is the output of the given code? for num in 1..3 puts num*num m= 0 loop do m += 1 puts m break if m == 3 end end

A.
12345678910
B.
1 1 2 3 4 1 2 3 9 1 2 3
C.
1 4 9 16 25
Answer
D.
None of the mentioned

Answer: Option C

Solution

Answer: Option C
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