Q390
What is the output of this program? #include #include int main() int fd; char buff[512]; if( mkfifo("/tmp/test_fifo",0666) == -1) perror("mkfifo"); fd = open("/tmp/test_fifo",O_RDONLY); read(fd,buff,512); printf("%s ",buff); return 0;
A.
this program will print the garbage of 512 bytes
B.
this program will print nothing
AnswerC.
segmentation fault
D.
none of the mentioned
Answer: Option B
Solution
Answer: Option B
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