What is the ratio whose terms differ by 40 and the measure of which is 2/7 ?

Answer: Option C

Let the terms of the ratio be x and x + 40
$$\begin{array}{rl}& \text{Then,}\\ & =\frac{x}{x+40}=\frac{2}{7}\\ & \Rightarrow 7x=2x+80\\ & \Rightarrow 5x=80\\ & \Rightarrow x=16\\ & \therefore \text{Required ratio}\\ & =16:56\end{array}$$