What is the slope of the line perpendicular to the line passing through the points (-5, 1) and (-2, 0)?

Answer: Option B

Slope of the line passing through the point (-5, 1) & (-2, 0)
$$m_1=\frac{0-1}{-2-\left(-5\right)}=\frac{-1}{3}\left[m=\frac{y_2-y_1}{x_2-x_1}\right]$$
Slope of the 1^st line $$=\frac{-1}{m_1}=\frac{-1}{\left(\frac{-1}{3}\right)}=3$$
(∴ If 2 lines are ⊥ then their slope m₁ × m₂ = -1)