What is the value of a[1] after the following code is executed? int[] a = 0, 2, 4, 1, 3; for(int i = 0; i < a.length; i++) a[i] = a[(a[i] + 3) % a.length];

Answer: Option B

Here's an explanation of the code:

1. The array a is initialized with values: {0, 2, 4, 1, 3}.
2. The for loop iterates over each element of the array using the variable i.
3. Inside the loop, the value of a[i] is updated using the expression a[(a[i] + 3) % a.length].
  (i) For i = 0, a[i] is 0. So, a[(0 + 3) % 5] becomes a[3 % 5] which is a[3] (value 1).
 (ii) For i = 1, a[i] is 2. So, a[(2 + 3) % 5] becomes a[5 % 5] which is a[0] (value 0).
 (iii) For i = 2, a[i] is 4. So, a[(4 + 3) % 5] becomes a[7 % 5] which is a[2] (value 4).
 (iv) For i = 3, a[i] is 1. So, a[(1 + 3) % 5] becomes a[4 % 5] which is a[4] (value 3).
 (v) For i = 4, a[i] is 3. So, a[(3 + 3) % 5] becomes a[6 % 5] which is a[1] (value 2).
4. After the loop finishes, the modified array a becomes {0, 1, 4, 3, 2}.
5. Finally, the code prints the value of a[1] using System.out.println(a[1]), which outputs 1.

Therefore, the output of the code is 1.