What will be the output of the following C code? #include int main() printf("Ram "); return 0;

Answer: Option B

The correct answer is Option B: Ram Shyam.

Here's why:

* `printf("Ram\rShyam\n");` is the core of the problem. Let's break it down:
* `Ram`: This part is initially printed to the console buffer.
* `\r`: This is the carriage return character. It moves the cursor to the beginning of the current line.
* `Shyam`: Because of `\r`, this overwrites the beginning of the existing line. So "Ram" is replaced by "Shyam". If "Shyam" has fewer characters than "Ram", some parts of "Ram" may remain.
* `\n`: This is the newline character. It moves the cursor to the beginning of the next line.
Because `\r` brings the cursor to the start of the line *before* "Shyam" is printed, "Shyam" will overwrite "Ram", and then `\n` will put the cursor on a newline for subsequent outputs (if any).