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C# Programming · Q66

Basic Syntax and Data Types in C Sharp

Programming · C# Programming · question 66

Q66

What will be the output of the following C# code? static void Main(string[] args) int i ; for (i = 0; i < 5; i++) int j = 0; j += i; Console. WriteLine(j); Console. WriteLine( i * j); Console. ReadLine();

A.
0, 1, 6, 18, 40
B.
0, 1, 5, 20, 30
C.
Compile time error
Answer
D.
0, 1, 2, 3, 4, 5

Answer: Option C

Solution

Answer: Option C
Solution:
Understanding the Code:
This C# code uses a for loop to repeat a block of code five times.
Inside the loop, a variable j is declared and initialized to 0 in each iteration.
Then, j is updated by adding the current value of i to it (j += i;).
The value of j is printed to the console in each iteration.
After the loop finishes, the code tries to print i * j. However, this is tricky! The scope of j is only inside the loop. Once the loop finishes, j no longer exists.
Therefore, you will get a compile-time error because j is not accessible outside the loop.

Why other options are incorrect:
Options A, B, and D show possible outputs if the code were to run without error. Since j is out of scope, these outputs are impossible.

The Correct Answer:
The correct answer is C: Compile time error because the variable j is not accessible outside the for loop.