Q46
What will be the output of the following Python code? def a(n): if n == 0: return 0 elif n == 1: return 1 else: return a(n-1)+a(n-2) for i in range(0,4): print(a(i),end=" ")
A.
0 1 2 3
B.
An exception is thrown
C.
0 1 1 2 3
D.
0 1 1 2
AnswerAnswer: Option D
Solution
Answer: Option D
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