Q121
What will be the worst case time complexity of the following code? #include using namespace std; void func(int arr[], int n) int count[n]; memset(count, 0, sizeof(count)); for (int i=n-2; i>=0; i--) if (arr[i] >= n - i - 1) count[i]++; for (int j=i+1; j < n-1 && j <= arr[i] + i; j++) if (count[j] != -1) count[i] += count[j]; if (count[i] == 0) count[i] = -1; for (int i=0; i<n; i++) cout << count[i] << " "; int main() int arr[] = 1, 3, 5, 8, 9; int n = sizeof(arr) / sizeof(arr[0]); func(arr, n); return 0;
A.
O(n1/2)
B.
O(n)
C.
O(n3/2)
D.
O(n2)
AnswerAnswer: Option D
Solution
Answer: Option D
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