When 12, 16, 18, 20 and 25 divide the least number x, the remainder in each case is 4 but x is divisible by 7. What is the digit at the thousand's place in x?

Answer: Option D

LCM of 12, 16, 18, 20, 25 = 3600
For remainder 4 = 3600k + 4
If divisible by 7 $$=\frac{7\times 514k+2k+4}{7}$$
$$\frac{2k+4}{7},$$  If k = 5 divisible
x = 3600 × 5 + 4
= 18000 + 4
$$=\underset{\boxed{8}}{\underset{\downarrow }{18004}}$$