When a number is divided by 5, the remainder is 3. What will be the remainder when sum of cube of that number and square of that number is divided by 5 ?

Answer: Option A

Let us assume any such number which when divided by 5 leaves remainder as 3.
Let it be 8
So, now
$$\begin{array}{rl}& =\frac{{\left(8\right)}^2+{\left(8\right)}^3}{5}\\ & =\frac{64+512}{5}\\ & =\frac{576}{5}=1\left[\text{Remainder}\right]\end{array}$$