When operated separately pipe A takes 5 hours less than pipe B to fill a cistern, and when operated together, the cistern gets filled in 6 hours. In how much time (in hours) will pipe A fill the cistern, if operated separately?

Answer: Option A

Solution

Answer: Option A

Solution:

\begin{array}{*{20}{c}} {\text{B}}&{}&{\text{A}} \\ {x + 5}&:&x \end{array}
Now go through option,
Let A = 10 hours
B = 15 hours

A + B = $$\frac{30}{5}$$ = 6 hours