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Mechanical Engineering · Q27

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Engineering and GATE · Mechanical Engineering · question 27

Q27

When the dimension is expressed as 20_ - 0.025^ + 0.035, then the tolerance is

When the dimension is expressed as  then the tolerance is
A.
0.035 mm
B.
0.025 mm
C.
0.01 mm
D.
0.06 mm
Answer

Answer: Option D

Solution

Answer: Option D
Solution:
Upper Limit = 20.000 + 0.035 = 20.035
Lower limit = 20.000 - 0.025 = 19.975
Tolerance = Upper Limit - Lower limit
= 20.035 - 19.975
= 0.06