x, y and z are distinct prime numbers where x < y < z. If x + y + z = 70, then what is the value of z?

Answer: Option C

Since x, y and z are distinct prime number (x < y < z)

y + z = 70 - 2 = 68
31 + 37 = 68
Hence, x = 2, y = 31 and $$\boxed{\text{z}=37}\text{ Answer}$$