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Aptitude · Q261

Ratio

Competitive Exams · Aptitude · question 261

Q261

y varies directly as (x + 3) and y = 8 when x = 1. What is the value of y when x = 2 ?

A.
6
B.
10
Answer
C.
12
D.
16

Answer: Option B

Solution

Answer: Option B
Solution:
y α (x + 3)
⇒ y = k (x + 3) for some constant k.
When y = 8, x = 1, y = k (x + 3)
⇒ 8 = k (1 + 3)
⇒ k = 2
When x = 2, y = 2(x + 3) = 2(2 + 3) = 2 × 5 = 10