Q12
You have an interface on a router with the IP address of 192.168.192.10/29. What is the broadcast address the hosts will use on this LAN?
A.
192.168.192.15
AnswerB.
192.168.192.31
C.
192.168.192.63
D.
192.168.192.127
Answer: Option A
Solution
Answer: Option A
Solution:
A /29 (255.255.255.248) has a block size of 8 in the fourth octet. This means the subnets are 0, 8, 16, 24, etc. 10 is in the 8 subnet. The next subnet is 16, so 15 is the broadcast address.