For the concentration cell, M|M+ (aq, 0.01 mol/dm3 )| |M+ (aq), 0.1 mol/dm3 |M the EMF (E) of the cell at a temperature (T) equals
A. 2.303 F R T
B. − 2.303 F R T
C. E M + ∣ m ∘ + 2.303 F R T
D. E M + ∣ m ∘ − 2.303 F R T
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The activity of water at 11 bar and 298 K is
A. 1.101
B. 1.007
C. 0.998
D. 0.898
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Given that E°(Fe3+ , Fe) = -0.4 V and E°(Fe2+ , Fe) = -0.44 V, the value of E°(Fe3+ , Fe2+ ) is
A. 0.76V
B. -0.40 V
C. -0.76 V
D. 0.40 V
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According to the Debye-Huckel limiting law, if the concentration of a dilute aqueous solution of KCl is increased 4-fold, the value of In γz (γz is the molar mean ionic activity coefficient) will
A. decrease by a factor of 2
B. increase by a factor of 2
C. decrease by a factor of 4
D. increase by a factor of 4
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Given the standard potential for the following half-cell reaction at 298 K,
Cu+ (aq) + e- → Cu(s); E° = 0.52 V
Cu2+ (aq) + e- → Cu+ (aq); E° = 0.16 V
Calculate the ΔG° (kJ) for the reaction, [2Cu+ (aq) → Cu(s) + Cu2+ ]
A. -34.740
B. -65.720
C. -69.480
D. -131.440
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A student recorded a polarogram of 2.0 mM Cd2+ solution and forget to add KCl solution. What type of error do you expect in his results?
A. Only migration current will be observed
B. Only diffusion current will be observed
C. Both migration current as well as diffusion current will be observed
D. Both catalytic current as well as diffusion current will be observed
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For a 2 molal aqueous NaCl solution, the mean ionic activity coefficient ( γ ± ) and the Debye-Huckel Limiting Law constant (A) are related as
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The standard reduction potentials at 298 K for single electrodes are given below.
Electrode
Electrode potential (volt)
Mg2+ /Mg
-2.34
Zn2+ /Zn
-0.76
Fe2+ /Fe
-0.44
From this we can infer that
A. Zn can reduce both Mg2+ and Fe2+
B. Fe can reduce both Mg2+ and Zn2+
C. Mg can reduce both Zn2+ and Fe2+
D. Mg can reduce Zn2+ but not Fe2+
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For the reaction, Hg2 Cl2 (s) + H2 (g) → 2Hg(liq) + 2HCl(aq), the correct representation of the cell and the thermodynamic properties ΔG, ΔH and ΔS at 298 K respectively, are (Given: E298 = 0.2684 V and temperature coefficient = 3 × 10-4 VK-1 )
A. Pt|H2 (g, 1 atm)|HCl(aq)|Hg2 Cl2 (g)|Hg(liq) ΔG = -51.8 kJ mol-1 , ΔH = -69 kJ mol-1 , ΔS = -58 JK-1 mol-1
B. Pt|H2 (g, 1 atm)|HCl(aq)|Hg2 Cl2 (g)|Hg(liq) ΔG = -25.9 kJ mol-1 , ΔH = -34.5 kJ mol-1 , ΔS = -29 JK-1 mol-1
C. Hg(liq)|H2 Cl2 (g)|HCl(aq)|H2 (g, 1 atm)|Pt ΔG = -51.8 kJ mol-1 , ΔH = -69 kJ mol-1 , ΔS = -58 JK-1 mol-1
D. Hg(liq)|H2 Cl2 (g)|HCl(aq)|H2 (g, 1 atm)|Pt ΔG = 51.8 kJ mol-1 , ΔH = 69 kJ mol-1 , ΔS = 58 JK-1 mol-1
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The Nernst equation for the reaction, A2+ + 2e- → B, in terms of the free energy change is
A. ΔG = ΔG° + 2.303 RT log [ A ] [ B ]
B. ΔG = ΔG° - 2.303 RT log [ A ] [ B ]
C. -ΔG = -ΔG° + 2.303 RT log [ A ] [ B ]
D. ΔG = -ΔG° + 2.303 RT log [ A ] [ B ]
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