A 680 Ω load resistor, RL, is connected across a constant current source of 1.2 A. The internal source resistance, RS, is 12 kΩ. The load current, RL, is

Answer: Option D

The load current is determined by analyzing the circuit and applying Ohm's law and the voltage-divider principle.

Given:

Load resistance, R_L = 680 Ω

Internal source resistance, R_S = 12 kΩ = 12,000 Ω

Constant current source, I_S = 1.2 A

Step 1: Determine the total voltage of the circuit

The total voltage generated by the current source is:

V_total = I_S × R_S = 1.2 A × 12,000 Ω = 14,400 V

Step 2: Calculate the equivalent resistance

The load resistor and internal source resistance form a voltage divider. The voltage across R_L is calculated as:

V_L = V_total × (R_L / (R_L + R_S))

V_L = 14,400 × (680 / (680 + 12,000))

V_L = 14,400 × (680 / 12,680) = 774 V

Step 3: Find the load current

The load current is:

I_L = V_L / R_L = 774 / 680 = 1.14 A