A man performs 2/15 of the total journey by rail, 9/20 by bus and the remaining 10 km, on the cycle. His total journey is :

Answer: Option D

Let the distance covered by man be x km
Journey covered by rail = $$\frac{2x}{15}$$
Journey covered by bus = $$\frac{9x}{20}$$
Remaining covered by cycle = 10 km
$$\begin{array}{rl}& \therefore x\left(1-\frac{2}{15}-\frac{9}{20}\right)=10\\ & \Rightarrow x\left(\frac{60-8-27}{60}\right)=10\\ & \Rightarrow x\left(\frac{25}{60}\right)=10\\ & \Rightarrow x=\frac{10\times 60}{25}\\ & \Rightarrow x=24\text{ km}\end{array}$$