A train covers a distance of 1931/3 km in 41/4 hours with one stoppage of 10 minutes, two of 5 minutes and one of 3 minutes on the way. The average speed of the train is :

Answer: Option B

Actual time taken for the journey :
= 4 hrs 15 min - (10 + 2 × 5 + 3) min
= 4 hrs 15 min - 23 min
= 3 hrs 52 min
= $$3\frac{26}{30}$$ hrs
= $$\frac{116}{30}$$ hrs
∴ Average speed :
$$\begin{array}{rl}& =\left(\frac{580}{3}\times \frac{30}{116}\right)\text{ km/hr}\\ & =50\text{ km/hr}\end{array}$$