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ECE · Q492

Signal Processing

Engineering and GATE · ECE · question 492

Q492

A signals m(t) with bandwidth 500 Hz is first multiplied by a signal g(t) where g ( t ) = _k = - ^ ( - 1 )^k ( t - 0.5 × 10^ - 4k ) The resulting signal is then passed through an ideal low pass filter with bandwidth 1 kHz. The output of the low pass filter would be

A signals m(t) with bandwidth 500 Hz is first multiplied by a signal g(t) where
The resulting signal is then passed through an ideal low pass filter with bandwidth 1 kHz. The output of the low pass filter would be
A.
δ(t)
B.
m(t)
C.
0
Answer
D.
m(t) δ(t)

Answer: Option C

Solution

Answer: Option C
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