Q26
ABCD is a parallelogram. BC is produced to Q such that BC = CQ. Then
A.
area (ΔABC) = area (ΔDCQ)
AnswerB.
area (ΔABC) > area (ΔDCQ)
C.
area (ΔABC) < area (ΔDCQ)
D.
area (ΔABC) ≠ area (ΔDCQ)
Answer: Option A
Solution
Answer: Option A
Solution:
In ΔABC & ΔDCQ
∠ABC = ∠DCQ
∠ACB = ∠DQC
BC = CQ
ΔABC ≅ ΔDCQ
ar ΔABC = ar ΔDCQ