The perimeter of a sheet of paper in the shape of a quadrant of a circle is 75 cm. Its area would be ( = 227 )

Answer: Option B

According to the figure,
⇒ Perimeter = r + r + $$l$$
⇒ 75 cm = 2r + length of arc
⇒ 75 cm = 2r + $$\frac{2\pi r}{4}$$
⇒ 75 cm = 2r + $$\frac{22\times r}{7\times 2}$$
⇒ r = 21 cm
⇒ Its area $$=\frac{1}{4}\left[\frac{22}{7}\times 21\times 21\right]=346.5\text{ c}{\text{m}}^2$$