For a constant pressure reversible process, the enthalpy change (ΔH) of the system is

Answer: Option C

By the definition of $$C_P$$ we can write $$C_P=\underset{\delta T\to 0}{\lim }{\left(\frac{\delta Q}{\delta T}\right)}_P.$$
Under constant pressure process, and by first law of thermodynamics $$Q=dH.$$
$$\begin{array}{rl}& \Rightarrow {\left(\frac{\partial H}{\partial T}\right)}_P=C_P\\ & \Rightarrow \Delta H=\int C_P.dT\end{array}$$