For any integral value of n, 32n + 9n + 5 when divided by 3 will leave the remainder

Answer: Option B

3²ⁿ + 9n + 5
Put n = 1
⇒ 3^{2 × 1} + 9 × 1 + 5
⇒ 9 + 9 + 5
⇒ 23 ⇒ $$\frac{23}{3}$$
⇒ remainder = 2
Note: value of n can be 1, 2, 3, 4, . . . . .