Q604
What least value which should be added to 1812 to make it divisible 7, 11 and 14?
A.
12
B.
36
AnswerC.
72
D.
154
Answer: Option B
Solution
Answer: Option B
Solution:
7, 11, 14, LCM = 154154k = 154 × 12 = 1848
1848 - 1812 = 36