If 3sec2θ + tanθ - 7 = 0, 0°

Question

If 3sec2θ + tanθ - 7 = 0, 0° < θ < 90°, then what is the value of ( 2 + 3 cosec\, + )?

Accepted Answer

Option C. 5/4. Answer & Solution Answer: Option C Solution: & 3 ^2 + - 7 = 0 & 3 ( 1 + ^2 ) + - 7 = 0 & 3 ^2 + - 4 = 0 & 3 ^2 + 4 - 3 - 4 = 0 & ( 3 + 4 ) - 1 ( 3 + 4 ) = 0 & ( 3 + 4 ) ( - 1 ) = 0 & = 1\,\,\,\,\,\,\,\,\, = 45^ & \, 2 + 3 cosec\, + & = 2 ( 1 2 ) + 3 ( 1 2 ) 2 + 2 & = 5 2 2 2 & =…