The value of sec228° - cot262° + sin260° + cosec230° is equal to:

Answer: Option D

$$\begin{array}{rl}& {\sec }^{2}28^{\circ }-{\cot }^{2}62^{\circ }+{\sin }^{2}60^{\circ }+\text{cose}{\text{c}}^{2}30^{\circ }\\ & ={\sec }^{2}28^{\circ }-{\tan }^{2}28^{\circ }+{\sin }^{2}60^{\circ }+\text{cose}{\text{c}}^{2}30^{\circ }\\ & =1+{\left(\frac{\sqrt{3}}{2}\right)}^2+{\left(2\right)}^2\\ & =1+\frac{3}{4}+4\\ & =\frac{23}{4}\end{array}$$