If the internal energy of an ideal gas decreases by the same amount as the work done by the system, then the

Answer: Option D

By first law of thermodynamics we can say $$\delta Q=dU+\delta W$$
$$\Rightarrow$$  for the internal energy and work to be same in magnitude we can say that heat transfer has to be zero $$\delta Q=0$$
So the process is adiabatic and given the system is ideal gas and its internal energy is decreasing so, we can say that temperature decreases since the internal energy of a substance is solely dependent of temperature.