If ΔABC is an isosceles triangle with ∠C = 90° and AC = 5 cm then AB is:

Answer: Option C

According to question,
Given: ∠C = 90°

BC = AC = 5 cm (Isosceles triangle)
By Pythagoras theorem
AB² = AC² + BC²
AB² = 5² + 5²
AB² = 25 + 25
AB² = 50
AB = 5$$\sqrt{2}$$ cm