O is the incentre of ΔABC and ∠A = 30°, then ∠BOC is

Answer: Option B

According to question,
Given:

∴ ∠BOC = 90° + $$\frac{1}{2}$$ ∠A
∠BOC = 90° + $$\frac{1}{2}$$ × 30°
∠BOC = 90° + 15°
∠BOC = 105°