In a circle with centre O, chords PR and QS meet at the point T, when produced, and PQ is a diameter. If ∠ROS = 42°, then the measure of ∠PTQ is:

Answer: Option D

PSQ = 90° (Angle in semicircle)
∠TPS = $$\frac{1}{2}$$∠ROS (Angle of same arc)
∠TPS = $$\frac{1}{2}$$ × 42° = 21°
In ΔPTS
21° + ∠PTS + 90° = 180°
∠PTG = 69° Answer