There are 8 equidistant points A, B, C, D, E, F, G and H (in same order) on a circle. What is the value of ∠FDH (in degrees)?

Answer: Option B

Solution

Answer: Option B

Solution:

$$\begin{array}{rl}& \angle FOH=\frac{\angle FOB}{2}=90^{\circ }\\ & \left[\therefore FOB\text{ is a straight line}\right]\\ & \angle HDF=\frac{\angle FOH}{2}=\frac{{90}^{\circ }}{2}=45^{\circ }\end{array}$$