In case of a reversible process (following pvn = constant), work obtained for trebling the volume (v1 = 1 m3 and v2 = 3 m3) is maximum, when the value of 'n' is

Answer: Option A

The work done for a process described by equation $$P{V}^n=\text{constant}\text{.}$$
Is given by $$w=\frac{C{V}_2^{1-n}-C{V}_1^{1-n}}{1-n}$$
So, the work obtained will be maximum when n is minimum so, $$n=0.$$