In ΔPQR, ∠P = 90°. S and T are the mid points of sides PR and PQ, respectively. What is the value of R Q^2 Q S^2 + R T^2 = ?

Answer: Option B

Solution

Answer: Option B

Solution:

$$\begin{array}{rl}& \text{RT }\&\text{ QS are medians}\\ & 5\text{Q}{\text{R}}^2=4\left(\text{Q}{\text{S}}^2+\text{R}{\text{T}}^2\right)\\ & \Rightarrow \frac{4}{5}=\frac{\text{Q}{\text{R}}^2}{\text{Q}{\text{S}}^2+\text{R}{\text{T}}^2}\end{array}$$