In ΔPQR, ∠Q = 84° and ∠R = 48°, PS ⊥ QR at S and the bisector of ∠P meets QR at T. What is the measure of ∠SPT ?

Answer: Option D

∠QPR = 180° - (84° + 48°) = 48°
∠QPT = $$\frac{{48}^{\circ }}{2}$$ = 24°
∠QPS = 6°
∠SPT + ∠SPQ = 24°
∠SPT + 6° = 24°
∠SPT = 18°