In what ratio is the segment joining points (2, 3) and (-2, 1) divided by the Y-axis?

Answer: Option B

$$\begin{array}{rl}& \frac{k:1}{\text{A}\left(-2,1\right)\text{C}\left(x,y\right)\text{B}\left(2,3\right)}\\ & \Rightarrow x=\frac{-2k+2}{k+1}\\ & \text{At }y\text{ - axis}\boxed{x=0}\\ & \therefore 0=\frac{-2k+2}{k+1}\\ & \Rightarrow \boxed{k=1}\\ & \text{Ratio}=1:1\end{array}$$